1=(-4/x-9)-(3/x-9)^2

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Solution for 1=(-4/x-9)-(3/x-9)^2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1 = -(3/x-9)^2-4/x-9 // + -(3/x-9)^2-4/x-9

(3/x-9)^2-(-4/x)+1+9 = 0

(3/x-9)^2+4*x^-1+1+9 = 0

(3*x^-1-9)^2+4/x+1+9 = 0

(x*(3*x^-1-9)^2)/x+4/x+(1*x)/x+(9*x)/x = 0

x*(3*x^-1-9)^2+1*x+9*x+4 = 0

81*x+x+9*x+9*x^-1-50 = 0

82*x+9*x+9*x^-1-50 = 0

91*x+9*x^-1-50 = 0

91*x+9*x^-1-50 = 0

91*x^1+9*x^-1-50*x^0 = 0

(91*x^2-50*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(91*x^2-50*x^1+9*x^0) = 0

x^1

91*x^2-50*x+9 = 0

91*x^2-50*x+9 = 0

DELTA = (-50)^2-(4*9*91)

DELTA = -776

DELTA < 0

x in { }

1 = 0

1/x = 0

1/x = 0 // * x

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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